Claim:Σi = n(n+1)/2

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Revision as of 14:10, 27 September 2018 by {{GENDER:Mdg39|[math]'"2}} [/math]'"7
(<math>1) </math>2 | <math>3 (</math>4) | <math>5 (</math>6)
Claim (see proof):
For all [math]n \href{/cs2800/wiki/index.php/%E2%88%88}{∈} \href{/cs2800/wiki/index.php/%E2%84%95}{ℕ} [/math], [math]\sum_{i=0}^n i = \frac{n(n+1)}{2} [/math]
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