Choose an arbitrary value

From CS2800 wiki

If your goal is to prove "for all [math]x\href{/cs2800/wiki/index.php/%E2%88%88}{∈}A [/math], P", you can proceed by choosing an arbitrary value [math]x∈A [/math] and then proving that P holds for that [math]x [/math].

The fact that [math]x [/math] is arbitrary does not mean you get to pick [math]x [/math]; on the contrary, your proof should work no matter what [math]x [/math] you choose. This means you can't use any property of [math]x [/math] other than that [math]x \href{/cs2800/wiki/index.php/%E2%88%88}{∈} A [/math].